Asked by HELP
A speedboat starts from rest and accelerates at 2.689x10^0 m/s2 for 6.5062x10^0 seconds. After that, the boat then accelerates at 1.7853x10^0 m/s 2 for 3.1299x10^0 seconds. What is the velocity of the boat at the end of this, expressed in 4 significant figures?
Answers
Answered by
Henry
V= a1t1 + a2t2,
= 2.689*6.5062 + 1.7853*3.1299,
= 17.495 + 5.5878 = 23.08 m/s
= 2.689*6.5062 + 1.7853*3.1299,
= 17.495 + 5.5878 = 23.08 m/s
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