Asked by Nisar

I have a hard time solving this problem.

The weight of an object at the surface of a planet is proportional to the planet's mass and inversely proportional to the square of the radius of the planet. Jupiter's radius is 11 times Earth's and its mass is 320 times Earth's. An apple weighs 1.0 N on Earth. How much would it weigh on Jupiter?


wouldn't one multiply by 320(proportional to mass) and divide by 11 squared (inversely proportional to the square of distance)?


2.6N
Answered by Amber
Yes I just had a problem like this too. You would multiply by 320 and divide by 11 squared. 2.6 N would be correct for 2 signifigant digits.
Answered by amy
The weight of an object at the surface of a planet is proportional to the planet's mass and inversely proportional to the square of the radius of the planet. Jupiter's radius is 11 times Earth's and its mass is 320 times Earth's. An apple weighs 1.0 N on Earth. How much would it weigh on Jupiter?
Answered by amy
In cleaning out the artery of a patient, a doctor increases the radius of the opening by a factor of two. By what factor does the cross-sectional area of the artery change?
Answered by amy
The average speed of a nitrogen molecule in air is proportional to the square root of the temperature in kelvins. If the average speed is 475 m/s on a warm summer day (temperature = 300.0 kelvins), what is the average speed on a cold winter day (250.0 kelvins)?
Answered by dgfs
gfd
Answered by sdsd
asadad