Asked by Nisar

I have a hard time solving this problem.

The weight of an object at the surface of a planet is proportional to the planet's mass and inversely proportional to the square of the radius of the planet. Jupiter's radius is 11 times Earth's and its mass is 320 times Earth's. An apple weighs 1.0 N on Earth. How much would it weigh on Jupiter?


wouldn't one multiply by 320(proportional to mass) and divide by 11 squared (inversely proportional to the square of distance)?


2.6N
Answered by Amber
Yes I just had a problem like this too. You would multiply by 320 and divide by 11 squared. 2.6 N would be correct for 2 signifigant digits.
Answered by amy
The weight of an object at the surface of a planet is proportional to the planet's mass and inversely proportional to the square of the radius of the planet. Jupiter's radius is 11 times Earth's and its mass is 320 times Earth's. An apple weighs 1.0 N on Earth. How much would it weigh on Jupiter?
Answered by amy
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