Asked by Missy
Aqueous sulfuric acid is neutralized by aqueous potassium hydroxide.
Express your answer as an ionic equation. Identify all of the phases in your answer.
Express your answer as an ionic equation. Identify all of the phases in your answer.
Answers
Answered by
DrBob222
2KOH + H2SO4 ==>2H2O + K2SO4
2K^+(aq) + 2OH^-(aq) + 2H^+(aq) + SO4^-2(aq) ==> 2H2O(l) + 2K^+(aq) + SO4^-2(aq)
The net ionic equation is
2OH^-(aq) + 2H^+(aq) ==> 2H2O(l)
Then I would divide by 2 to give simply
OH^-(aq) + H^+(aq) --> H2O(l) but your prof may frown on not putting the coefficients there.
2K^+(aq) + 2OH^-(aq) + 2H^+(aq) + SO4^-2(aq) ==> 2H2O(l) + 2K^+(aq) + SO4^-2(aq)
The net ionic equation is
2OH^-(aq) + 2H^+(aq) ==> 2H2O(l)
Then I would divide by 2 to give simply
OH^-(aq) + H^+(aq) --> H2O(l) but your prof may frown on not putting the coefficients there.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.