The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams of water?

6 answers

1 g = 540 calories
500 g = ? calories

Since the mass is 500 times 1 g, so the number of calories
= 500*540 calories
Oh, so you just set it up like a proportion?
And thank you. (:
wah
it is 270000
It is not called a PROPORTION
It is called a MULTIPLICATION
Given,
heat of vaporization of water is 540 cal per gram
therefore amount of heat required
( 500 × 540) cal
is equal to 270000 calories...