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The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams...Asked by Katy
The latent heat of vaporization of water is 540 calories/gram. How many calories are required to completely vaporize 500 grams of water?
Answers
Answered by
MathMate
1 g = 540 calories
500 g = ? calories
Since the mass is 500 times 1 g, so the number of calories
= 500*540 calories
500 g = ? calories
Since the mass is 500 times 1 g, so the number of calories
= 500*540 calories
Answered by
Katy
Oh, so you just set it up like a proportion?
And thank you. (:
And thank you. (:
Answered by
bob
wah
Answered by
Anonymous
it is 270000
Answered by
Colin Mitchell
It is not called a PROPORTION
It is called a MULTIPLICATION
It is called a MULTIPLICATION
Answered by
Treshika
Given,
heat of vaporization of water is 540 cal per gram
therefore amount of heat required
( 500 × 540) cal
is equal to 270000 calories...
heat of vaporization of water is 540 cal per gram
therefore amount of heat required
( 500 × 540) cal
is equal to 270000 calories...
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