Asked by Anonymous
what is x^2+54+800 in vertex form?
Answers
Answered by
Henry
Y = X^2 + 54X + 800.
Vertex form:
y = a(x - h)^2 + k,
h = Xv = -b/2a = -54/2 = -27,
Substitute -27 for x in quad. Eq:
k = Yv = (-27)^2 + 54*(-27) + 800 = 71.
a = 1 = coefficient of x^2.
Eq: y = (x + 27)^2 + 71.
Vertex form:
y = a(x - h)^2 + k,
h = Xv = -b/2a = -54/2 = -27,
Substitute -27 for x in quad. Eq:
k = Yv = (-27)^2 + 54*(-27) + 800 = 71.
a = 1 = coefficient of x^2.
Eq: y = (x + 27)^2 + 71.
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