Question

A driving bell is a container open at the bottom. As the bell descends, the water level inside changes so that the pressure inside equals the pressure outside. Intially the volume of air is 8.58m^3 at 1.020 atm and 20 degrees C. What is the volume at 1.584 atm and 20 degrees C.

V1= 20.0 L
V2= ?
P1= 1.020 atm
P2= 1.584 atm

V2= 20.0 L * 1.020/1.584=

ANSWER 12.8787

Is this correct

Answer 1

Did you copy 20 degrees C for V1 = 20.0 L. The problem says 8.58 m³.

Answer 2

Sorry it should be 8.58 * 1.020/ 1.584=

Answer:

5.525 m^3

Is that right now

Answer 3

yes

Answer 4

Thanks for all the help DrBob I really appreciate it