Asked by amy
A solution contains 0.245 of dissolved lead (lead ion or Pb2+.)
How many moles of sodium chloride must be added to the solution to completely precipitate all of the dissolved lead?
What mass of sodium chloride must be added?
How many moles of sodium chloride must be added to the solution to completely precipitate all of the dissolved lead?
What mass of sodium chloride must be added?
Answers
Answered by
DrBob222
Pb^+2 + 2NaCl --> PbCl2 + 2Na^+
Convert 0.245 g Pb^+2 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles Pb to moles NaCl. That gives you part a.
Convert moles NaCl to grams. g = moles x molar mass. That gives you part b.
Convert 0.245 g Pb^+2 to moles. moles = grams/molar mass
Using the coefficients in the balanced equation, convert moles Pb to moles NaCl. That gives you part a.
Convert moles NaCl to grams. g = moles x molar mass. That gives you part b.
Answered by
Kristina
0.00097973
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