If you meant g(θ) = (cos(8θ))^9 then
g ' (θ) = 9(cos(8θ))^8 * (-8sin(8θ))
Please help, thank you!!!
Find the derivative of the function.
g(θ) = (cos(8θ))9
5 answers
is (cos(8x))^8 = (cos8x)^8
Some "purist" would claim that cos8x
would mean , take the cos8 then multiply that by x
to be safe, write it as cos(8x)
would mean , take the cos8 then multiply that by x
to be safe, write it as cos(8x)
thank you so much :D
Could you please help me with this one too?? Thank you. Find d/dx for (sin πx + cos πy)4 = 65
1 answer