Asked by LINDA
I have to make it so the results
of the average is less than 25.
Average of three volumes:
13+11.3+9.2= 33.5/ 3= 11.16 mL
Convert mL to L
11.16 mL x 10^-3 L = .01116 L
The number of moles of HCl was calculated using the stoichiometry :
1 mole HCl= ½ moles CO3
.01116 L x 1.0 mol = .01116 mol HCl
---------
1 L
The number of moles of CO3 was calculated:
.01116/ 2 = .00558 mol CO3
The molar mass of CO3 was determined by using the equation (mass of unknown/mole CO3):
0.75 g unknown/ .00558 mol CO3= 134.40 g/mol CO3
The Molarities of CO3 was determined by:
CO3= 12+16+16+16=60 g
134.40 g/mol – 60 g =74.4 mol/2 =37.2 g/ mol
of the average is less than 25.
Average of three volumes:
13+11.3+9.2= 33.5/ 3= 11.16 mL
Convert mL to L
11.16 mL x 10^-3 L = .01116 L
The number of moles of HCl was calculated using the stoichiometry :
1 mole HCl= ½ moles CO3
.01116 L x 1.0 mol = .01116 mol HCl
---------
1 L
The number of moles of CO3 was calculated:
.01116/ 2 = .00558 mol CO3
The molar mass of CO3 was determined by using the equation (mass of unknown/mole CO3):
0.75 g unknown/ .00558 mol CO3= 134.40 g/mol CO3
The Molarities of CO3 was determined by:
CO3= 12+16+16+16=60 g
134.40 g/mol – 60 g =74.4 mol/2 =37.2 g/ mol
Answers
Answered by
DrBob222
I have to make it so the results
of the average is less than 25.
Average of three volumes:
13+11.3+9.2= 33.5/ 3= 11.16 mL
<b>I think the average is 11.166666 which rounds to 11.17 (and you will need to change it for the next problem.</b>
Convert mL to L
11.16 mL x 10^-3 L = .01116 L
<b> OK but with the new number. Also, I would show 10^-3 L/mL so the problem would look this way.
11.17 mL x 10^-3 L/mL = </b>
I don't understand the remainder of the question.
of the average is less than 25.
Average of three volumes:
13+11.3+9.2= 33.5/ 3= 11.16 mL
<b>I think the average is 11.166666 which rounds to 11.17 (and you will need to change it for the next problem.</b>
Convert mL to L
11.16 mL x 10^-3 L = .01116 L
<b> OK but with the new number. Also, I would show 10^-3 L/mL so the problem would look this way.
11.17 mL x 10^-3 L/mL = </b>
I don't understand the remainder of the question.
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