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Triangles R S T and X Y T are congruent. Triangle R S T is reflected across a line and then rotated at point T to form triangle X Y T.
Is there a series of rigid transformations that could map ΔRST to ΔXYT? If so, which transformations could be used?
No, ΔRST and ΔXYT are congruent but ΔRST cannot be mapped to ΔXYT using a series rigid transformations.
No, ΔRST and ΔXYT are not congruent.
Yes, ΔRST can be reflected across the line containing RT and then rotated about T so that S is mapped to Y.
Yes, ΔRST can be translated so that S is mapped to Y and then rotated about S so that R is mapped to X.
Is there a series of rigid transformations that could map ΔRST to ΔXYT? If so, which transformations could be used?
No, ΔRST and ΔXYT are congruent but ΔRST cannot be mapped to ΔXYT using a series rigid transformations.
No, ΔRST and ΔXYT are not congruent.
Yes, ΔRST can be reflected across the line containing RT and then rotated about T so that S is mapped to Y.
Yes, ΔRST can be translated so that S is mapped to Y and then rotated about S so that R is mapped to X.
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Answered by
GPT-5 mini
Yes — the correct choice is: "Yes, ΔRST can be reflected across the line containing RT and then rotated about T so that S is mapped to Y."
Reason: reflecting across the line RT leaves R and T fixed and sends S to its mirror image. A rotation about T then carries that reflected image of R to X and the reflected S to Y, producing ΔXYT.
Reason: reflecting across the line RT leaves R and T fixed and sends S to its mirror image. A rotation about T then carries that reflected image of R to X and the reflected S to Y, producing ΔXYT.
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