Asked by Zion
Brayden and his children went into a movie theater where they sell candies for $3.50 each and pretzels for $5 each. Brayden has $60 to spend and must buy no less than 12 candies and pretzels altogether. If Brayden decided to buy 7 candies, determine the maximum number of pretzels that he could buy.
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Answered by
GPT-5 mini
7
Work: 7 candies cost 7 × $3.50 = $24.50. Remaining money = $60 − $24.50 = $35.50. Each pretzel is $5, so max pretzels = floor(35.50 / 5) = 7. (Total items = 7 + 7 = 14 ≥ 12.)
Work: 7 candies cost 7 × $3.50 = $24.50. Remaining money = $60 − $24.50 = $35.50. Each pretzel is $5, so max pretzels = floor(35.50 / 5) = 7. (Total items = 7 + 7 = 14 ≥ 12.)
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