Asked by Doris
A sample of magnesium with a mass of 1.00 g is burned in oxygen to produce an oxide with a mass of 1.66 g. What is the empirical formula of the magnesium oxide produced? I know the answer is MgO. What are the steps to get that answer?
Answers
Answered by
DrBob222
Convert grams to moles.
1.00 g Mg/ 24.3 = moles Mg
g Osygen = 1.66-1.00 = 0.66
moles oxygen = 0.66/16 = moles O.
Now find the ratio of the two in and round to whole numbers. You will find 1:1 ratio.
1.00 g Mg/ 24.3 = moles Mg
g Osygen = 1.66-1.00 = 0.66
moles oxygen = 0.66/16 = moles O.
Now find the ratio of the two in and round to whole numbers. You will find 1:1 ratio.
Answered by
Dery
DrBob222 messed up at the oxygen, it should be O2 not O. so it would be:
Convert grams to moles.
1.00 g Mg/ 24.3 = 0.0411... moles Mg
g Oxygen = 1.66-1.00 = 0.66 g
moles oxygen = 0.66/32 = 0.0206... moles O.
Now find the ratio of the two in and round to whole numbers. You will find 2:1 ratio. (Mg2O)
Convert grams to moles.
1.00 g Mg/ 24.3 = 0.0411... moles Mg
g Oxygen = 1.66-1.00 = 0.66 g
moles oxygen = 0.66/32 = 0.0206... moles O.
Now find the ratio of the two in and round to whole numbers. You will find 2:1 ratio. (Mg2O)
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