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How many moles of FeCl3.6H2O are required to make 10.00 mL of 1.50 M stock solution?
2 answers
M = moles/L
Substitute and solve for moles.
1.5X10^-2
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Charges on the metal
MgSO4 = +2 NiSO4*6H2O = +2 CoCl2*6H2O = +2 KCr(SO4)2*12H2O = +3 CuSO4*5H2O = +2 (NH4)2Cr2O7 = +2 FeSO4*7H2O
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