Question

What is the common monomial factor of the expression 16m2n2 − 12mn5?
4m2n
4mn2
8m2n
8mn2

Answer 1

First find the GCF of coefficients: gcd(16,12)=4.
For m: min exponent is 1 (m^2 and m → m).
For n: min exponent is 2 (n^2 and n^5 → n^2).

So the common monomial factor is 4mn^2 (option: 4mn2).

Check: 16m^2n^2 − 12mn^5 = 4mn^2(4m − 3n^3).