Asked by Kavi
You are given a vector in the xy plane that has a magnitude of 100.0 units and a y component of -50.0 units
(b) Assuming the x component is known to be positive, specify the vector which, if you add it to the original one would give a resultant vector that is 85.0 units long and points entirely in the -x direction.
Magnitude ?
Direction ?
(b) Assuming the x component is known to be positive, specify the vector which, if you add it to the original one would give a resultant vector that is 85.0 units long and points entirely in the -x direction.
Magnitude ?
Direction ?
Answers
Answered by
Henry
Y = ver = -50 (given),
X^2 + (-50)^2 = (100)^2,
X^2 = 10000 - 2500 = 7500,
X = hor = sqrt(7500) = 86.6,
Vector to be added:
-50 + Y = 0,
Y = 50 added.
86.6 + X = -85,
X = hor = -85 - 86.6 = -171.6 added.
tanA = Y/X = 50/171.6 = 0.2914,
A = 16.24 deg.
Magnitude = y / sinA = 50/sin16.24
= 178.7
Direction = 16.24 deg above WEST.
X^2 + (-50)^2 = (100)^2,
X^2 = 10000 - 2500 = 7500,
X = hor = sqrt(7500) = 86.6,
Vector to be added:
-50 + Y = 0,
Y = 50 added.
86.6 + X = -85,
X = hor = -85 - 86.6 = -171.6 added.
tanA = Y/X = 50/171.6 = 0.2914,
A = 16.24 deg.
Magnitude = y / sinA = 50/sin16.24
= 178.7
Direction = 16.24 deg above WEST.
Answered by
Henry
Correction:
Direction = 16.24 deg NORTH of WEST.
Direction = 16.24 deg NORTH of WEST.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.