Asked by sandhya
A rocket has an exhaust gas velocity of 2329 m/s and an expelled gas rate of 6761 kg/s. If it has a mass of 1.82 × 10^6 kg what is its initial acceleration ?
Answers
Answered by
drwls
According to Newton's Second Law
acceleration = (Thrust-Weight)/Mass
The Thrust of the rocket is
T =(exhaust velocity)*(mass loss rate)
= 1.57*10^7 N
(That ranks it among the largest rockets)
Weight = 1.78*10^7 N
a = 0.21*10^7/(1.82*10^6) = 1.1 m/s^2
That is the initial acceleration rate. The acceleration rate increases as mass is lost as exhaust.
acceleration = (Thrust-Weight)/Mass
The Thrust of the rocket is
T =(exhaust velocity)*(mass loss rate)
= 1.57*10^7 N
(That ranks it among the largest rockets)
Weight = 1.78*10^7 N
a = 0.21*10^7/(1.82*10^6) = 1.1 m/s^2
That is the initial acceleration rate. The acceleration rate increases as mass is lost as exhaust.
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