Question

Use any method to locate the zeros of y=−3x2+12x+15
.(1 point)
Responses

(0,15)
left parenthesis 0 comma 15 right parenthesis

(1,0)(−5,0)
left parenthesis 1 comma 0 right parenthesis left parenthesis negative 5 comma 0 right parenthesis

(−1,0)(5,0)
left parenthesis negative 1 comma 0 right parenthesis left parenthesis 5 comma 0 right parenthesis

There are no zeros.

Answer 1

Solve -3x^2 + 12x + 15 = 0. Divide by -3: x^2 - 4x - 5 = 0.
Factor: (x - 5)(x + 1) = 0, so x = 5 or x = -1.

Zeros: (5, 0) and (-1, 0).