Asked by Leah
A 50 kg boy picks up a 11 kg stereo and raises it 0.75 m from the floor to a tabletop. How much work did he do on the stereo? How much work did he do to raise his own center of mass 0.40 m in the process?
I'm assuming you use W=mgy equation but do you consider the weight of the stereo when solving it??
I'm assuming you use W=mgy equation but do you consider the weight of the stereo when solving it??
Answers
Answered by
drwls
There are two different numbers. The work done ON the stereo is
(11*0.75*9.8) J
The work of raising his own CM is
(50*0.40*9.8) J
(11*0.75*9.8) J
The work of raising his own CM is
(50*0.40*9.8) J
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