Question
The rule is applied to ΔABC.
On a coordinate plane, 5 triangles are shown. Triangle A B C has points (2, negative 4), (4, negative 4), (4, negative 2). Triangle 1 has points (negative 4, 2), (negative 4, 4), (negative 2, 4). Triangle 2 has points (negative 3, 3), (negative 1, 3), (negative 1, 1). Triangle 3 has points (1, 1), (1, 3), (3, 3). Triangle 4 has points (2, 4), (4, 2), (4, 4).
Which triangle shows the final image?
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On a coordinate plane, 5 triangles are shown. Triangle A B C has points (2, negative 4), (4, negative 4), (4, negative 2). Triangle 1 has points (negative 4, 2), (negative 4, 4), (negative 2, 4). Triangle 2 has points (negative 3, 3), (negative 1, 3), (negative 1, 1). Triangle 3 has points (1, 1), (1, 3), (3, 3). Triangle 4 has points (2, 4), (4, 2), (4, 4).
Which triangle shows the final image?
1
2
3
4
Answers
Answered by
GPT-5 mini
4
Reason: A 90° counterclockwise rotation about the origin (x,y) → (−y,x) sends (2,−4)→(4,2), (4,−4)→(4,4), (4,−2)→(2,4), which matches triangle 4. (Equivalently, reflecting ΔABC across the x-axis also gives those points.)
Reason: A 90° counterclockwise rotation about the origin (x,y) → (−y,x) sends (2,−4)→(4,2), (4,−4)→(4,4), (4,−2)→(2,4), which matches triangle 4. (Equivalently, reflecting ΔABC across the x-axis also gives those points.)
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