Question

A jar contains 2 green marbles, 4 blue marbles, 3 yellow marbles, and 2 black
marbles. A marble is chosen at random from the jar and replaced. Then a second
marble is chosen at random. Find the probability of the first marble being green
and the second marble being yellow.
6
⁄121
= 4.96%
3
⁄121
= 2.48%
4
⁄121
= 3.31%
5
⁄121
= 4.13%
8
⁄121
= 6.61%

Answer 1

P(first green) = 2/11, P(second yellow) = 3/11 (replacement ⇒ independent).
Probability = (2/11)(3/11) = 6/121 ≈ 4.96%.