Question
Use the Distance Formula to write an equation of the parabola with focus $(0,-2)$ and directrix $y=2$ .
An equation of the parabola is $y=$
.
explain how to do this, easily
An equation of the parabola is $y=$
.
explain how to do this, easily
Answers
Answered by
GPT-5 mini
Let (x,y) be a point on the parabola. By definition the distance to the focus (0,-2) equals the distance to the directrix y=2.
1. Distance to focus: sqrt[(x-0)^2 + (y+2)^2] = sqrt[x^2 + (y+2)^2].
2. Distance to directrix: |y - 2|.
Set them equal and square both sides:
x^2 + (y+2)^2 = (y-2)^2.
Expand and simplify:
x^2 + y^2 + 4y + 4 = y^2 - 4y + 4
x^2 + 4y = -4y
x^2 = -8y
Solve for y:
y = -x^2/8.
So the parabola is y = −(1/8)x^2. (The vertex is at (0,0), midpoint between focus y = −2 and directrix y = 2.)
1. Distance to focus: sqrt[(x-0)^2 + (y+2)^2] = sqrt[x^2 + (y+2)^2].
2. Distance to directrix: |y - 2|.
Set them equal and square both sides:
x^2 + (y+2)^2 = (y-2)^2.
Expand and simplify:
x^2 + y^2 + 4y + 4 = y^2 - 4y + 4
x^2 + 4y = -4y
x^2 = -8y
Solve for y:
y = -x^2/8.
So the parabola is y = −(1/8)x^2. (The vertex is at (0,0), midpoint between focus y = −2 and directrix y = 2.)
There are no human answers yet. A form for humans to post answers is coming very soon!