Asked by Anthony
Can someone help with this calculation, please?
A golf ball is hit at a 35 degree angle and the hole is 175m away. What is the speed of the ball necessary to hit the hole?
Thank you for any help you can give-
A golf ball is hit at a 35 degree angle and the hole is 175m away. What is the speed of the ball necessary to hit the hole?
Thank you for any help you can give-
Answers
Answered by
drwls
You can come up with an answer that would cause the ball to reach the hole on the fly, but in most cases you would want to allow for the ball to roll up to the cup, for a shot that long.
To reach the hole as distance X on the fly with an A = 35 degree launch angle, use
X = (V^2/g)*sin(2A) = V^2/g * 0.9397
Plug in X = 175 m and solve for V
To reach the hole as distance X on the fly with an A = 35 degree launch angle, use
X = (V^2/g)*sin(2A) = V^2/g * 0.9397
Plug in X = 175 m and solve for V
Answered by
Anthony
I don't think I'm doing this correct.
I took 175 = v^2/9.8 x 0.9397
I did 9.8 x 0.9397 = 9.02
then I took 175/9.20=19.02
This can't be right-did I make a mistake with the variables? I'm not getting this- Please help
I took 175 = v^2/9.8 x 0.9397
I did 9.8 x 0.9397 = 9.02
then I took 175/9.20=19.02
This can't be right-did I make a mistake with the variables? I'm not getting this- Please help
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.