You can come up with an answer that would cause the ball to reach the hole on the fly, but in most cases you would want to allow for the ball to roll up to the cup, for a shot that long.
To reach the hole as distance X on the fly with an A = 35 degree launch angle, use
X = (V^2/g)*sin(2A) = V^2/g * 0.9397
Plug in X = 175 m and solve for V
Can someone help with this calculation, please?
A golf ball is hit at a 35 degree angle and the hole is 175m away. What is the speed of the ball necessary to hit the hole?
Thank you for any help you can give-
2 answers
I don't think I'm doing this correct.
I took 175 = v^2/9.8 x 0.9397
I did 9.8 x 0.9397 = 9.02
then I took 175/9.20=19.02
This can't be right-did I make a mistake with the variables? I'm not getting this- Please help
I took 175 = v^2/9.8 x 0.9397
I did 9.8 x 0.9397 = 9.02
then I took 175/9.20=19.02
This can't be right-did I make a mistake with the variables? I'm not getting this- Please help