Question

Which quadratic function has a range that can be described as y ≤ 10.5? (1 point)
f (x) = 10.5(x-4)2-6
f(x) =6(x +4)2 + 10.5
f (2) = -6(+4) + 10.5
f(x) =-6(x - 10.5)2 +4

Answer 1

The range y ≤ 10.5 means the parabola opens downward and has vertex y-value 10.5, so it must be of form f(x) = -a(x - h)^2 + 10.5 (a>0). The choice intended to be that is the third one: f(x) = -6(x + 4)^2 + 10.5.