The initial horizontal velocity component is Vo. It equals the horizontal component when it his the floor.
(a) The time to fall H = 1.3 m, with no initial velocity component, is
T = sqrt(2H/g) = 0.515 s
(b) Vy at t = T = -g*T
c) The initial direction is horizontal. They tell you that. Vo = Vx = (2.2 m)/T = 4.27 m/s
d) Vx remains Vo
A spring gun launches a ball horizontally from 1.3 m above the floor. the ball strikes the floor 2.2m away, measured horizontally. Calculate
A .. the time the ball is flight
B... the vertical component of its velocity at the time it strikes the floor
C.... the initial velocity Vo ( magnitude and direction).
D...the horizontal component of its velocity as it hits the floor
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