Asked by Noelle
When 112 g of water at a temperature of 22.5°C is mixed with 65.1 g of water at an unknown temperature, the final temperature of the resulting mixture is 46.3°C. What was the initial temperature of the second sample of water?
Answers
Answered by
DrBob222
loss heat hot water + gain of heat by cold water = 0
[Mass1H2O x specific heat x (Tfinal-Tinitial)] + [mass2H2O x specific heat x (Tfinal-Tinitial)] = 0
[Mass1H2O x specific heat x (Tfinal-Tinitial)] + [mass2H2O x specific heat x (Tfinal-Tinitial)] = 0
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