Question

The frictional force of a 2.0-kg block of wood on a wooden table is 3.8 N. If you push the block with a force of 11.8 N, what is its acceleration across the table?

Answer 1

Net force = applied − friction = 11.8 N − 3.8 N = 8.0 N.
a = F_net / m = 8.0 N / 2.0 kg = 4.0 m/s² (in the direction of the push).