Question

If a line can be represented by the equation y+2=13(x−12)
, which of the following sets of points lies on the line?(1 point)
Responses

(−12,2)
and (−11,3)
left parenthesis negative 12 comma 2 right parenthesis and left parenthesis negative 11 comma 3 right parenthesis

(−12,2)
and (−9,3)
left parenthesis negative 12 comma 2 right parenthesis and left parenthesis negative 9 comma 3 right parenthesis

(12,−2)
and (13,1)
left parenthesis 12 comma negative 2 right parenthesis and left parenthesis 13 comma 1 right parenthesis

(12,−2)
and (15,−1)

Answer 1

Rearrange: y = 13x − 158.

Check the points:
- For (12, −2): y = 13(12) − 158 = 156 − 158 = −2 — this point is on the line.
- For (13, 1): y = 13(13) − 158 = 169 − 158 = 11 ≠ 1.
- For (15, −1): y = 13(15) − 158 = 195 − 158 = 37 ≠ −1.
- The negative-x points also do not satisfy the equation.

So only (12, −2) lies on the line; none of the given pairs has both points on the line.