Question

Graph of a line on a coordinate plane with labeled points: (negative 2,8), (negative 1,5), (0,2), (1, negative 1), and (2, negative 4).
Given the graph of a linear function, find the linear equation of the graph in point-slope form. What is the missing value needed to finish the point-slope form of the equation?

(1 point)
The point-slope form of the equation is y− Blank =−3(x−1)
.

Answer 1

The missing value is -1.

So the equation is y − (−1) = −3(x − 1), or equivalently y + 1 = −3(x − 1).