How many nutritional Calories does my body use when I consume a glass of 32.0 degree F. ice water, which contains 200. mL of liquid water and 30.0 grams of ice (body temperature 98.6 degree F)

Answer 1

It takes heat to melt the ice.
q = mass ice x heat fusion = 30 g x 80 cal/g = ??

It takes heat to raise the temperature of 230 g H2O (assume the water has a density of 1.00 g/mL) to body temperature (and we assume no heat is lost to the surroundings.)
q = 230g x specific heat water x (Tfinal-Tinitial).
specific heat is 1 cal/g
Tfinal = 98.6F converted to celsius.
Tinitial = 0
Add the two qs together for total calories. Then divide by 1000; I'm assuming you are calling a nutritional Calorie (a BIG calorie;i.e., a kcal, as opposed to a small calorie in real terms.)Check my thinking.