The boy on the tower of height h = 20 m in the figure below throws a ball a horizontal distance of x = 56 m. At what speed, in m/s, is the ball thrown?

Answer 1

The product of the horizontal velocity at which it is thrown (Vx) and the time required to fall 20 m (T) equals the horizontal distance travelled, which you have been given.

Vx = 56 m/T

(1/2)gT^2 = 20
T = sqrt(40m/g)

Solve for the horizontal velocity

Answer 2

29

Answer 3

sorry don't listen to that answer