Asked by Missy*
In the Haber-Bosch process, nitrogen and hydrogen gas are reacted under high temperature 500 degrees C and pressure 200 atm to form ammonia gas (NH3) according to the following equation: N2+3H2 = 2NH3
If 9300 L H2 gas is reacted with an excess of N2 gas at 200 atm and 500 degrees C, how many moles of ammonia gas would be produced, assuming a 15% yield?
If 9300 L H2 gas is reacted with an excess of N2 gas at 200 atm and 500 degrees C, how many moles of ammonia gas would be produced, assuming a 15% yield?
Answers
Answered by
DrBob222
You work this stoichiometry problem. Here is the link again.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Multiply the moles NH3 produced by 0.15 to correct for 15% yield and not 100% yield.
http://www.jiskha.com/science/chemistry/stoichiometry.html
Multiply the moles NH3 produced by 0.15 to correct for 15% yield and not 100% yield.
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