Asked by Missy*
A sample of natural gas at STP is 78% CH4 and 22% C2H6 by volume how many moles of each gas are present in 1.60L of the mixture?
Answers
Answered by
DrBob222
L CH4 = 1.60 x 0.78 = ??
L C2H6 = 1.60 x 0.22 = ??
moles = L/22.4
L C2H6 = 1.60 x 0.22 = ??
moles = L/22.4
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