Asked by Missy*

A sample of natural gas at STP is 78% CH4 and 22% C2H6 by volume how many moles of each gas are present in 1.60L of the mixture?

Answers

Answered by DrBob222
L CH4 = 1.60 x 0.78 = ??
L C2H6 = 1.60 x 0.22 = ??
moles = L/22.4
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions