Question

if .01 moles of nitric acid dissolved in 10 liters of water what concentration of acid would it produce?

Answer 1

Molarity = moles / volume = 0.01 mol / 10 L = 0.001 mol·L⁻¹ = 1.0 × 10⁻³ M (1.0 mM).

Since HNO3 is a strong acid (fully dissociates), [H+] ≈ 0.001 M, so pH = −log10(0.001) = 3.00.