Asked by Help asap!! plz
Hi,
I am lost on couple of problems and i was wondering if you could just help me out with them.
1. Find and classify the points of discontinuity of the function F(x) = (x^2+7x+12)/(x^3-9x)
now for this problem i know there is going to be an infinite discontinuity because of the asymptotes, but at what points? is it going to be at x=3 x=-3 x=0 OR since after factoring top and bottom the result is (x+4)/x(x-3) so is it going to be just x=0 x=3
Also, how does canceling after factoring affect the graph; does that mean there is going to be a hole (and a removable discontinuity)? I kind of forgot this from precalculus.
2. Find all points where the tangent line to y=x^3-6x+12 has slope -1.
-lost on this one
3. Use the table below, which shows values of f(x) for x near 2, to find the slope of a secant line that is an estimate for f '(2)
x 1.8 1.9 2.0 2.1 2.2
f(x) 2.24 2.27 2.30 2.33 2.37
4. F(x) = x^2 if x<1
4-kx if x >or equal to 1
For the value of k, is f(x) differentiable at x=1? explain your answer
got 3 for the value of k
I am lost on couple of problems and i was wondering if you could just help me out with them.
1. Find and classify the points of discontinuity of the function F(x) = (x^2+7x+12)/(x^3-9x)
now for this problem i know there is going to be an infinite discontinuity because of the asymptotes, but at what points? is it going to be at x=3 x=-3 x=0 OR since after factoring top and bottom the result is (x+4)/x(x-3) so is it going to be just x=0 x=3
Also, how does canceling after factoring affect the graph; does that mean there is going to be a hole (and a removable discontinuity)? I kind of forgot this from precalculus.
2. Find all points where the tangent line to y=x^3-6x+12 has slope -1.
-lost on this one
3. Use the table below, which shows values of f(x) for x near 2, to find the slope of a secant line that is an estimate for f '(2)
x 1.8 1.9 2.0 2.1 2.2
f(x) 2.24 2.27 2.30 2.33 2.37
4. F(x) = x^2 if x<1
4-kx if x >or equal to 1
For the value of k, is f(x) differentiable at x=1? explain your answer
got 3 for the value of k
Answers
Answered by
drwls
Your chances of getting questions answered promptly, or at all, greatly improve if you post them one at a time. Many of the volunteers here do no have time to answer four questions of this complexity in one sitting.
Let's consider question #2:
The slope to the tangent line of a function f(x) is f'(x) = df/dx
Thus you want to know where
f'(x) = 3x^2 -6 = -1
3x^2 = 5
x = +or- sqrt(5/3)
= +1.291 or -1.291
Let's consider question #2:
The slope to the tangent line of a function f(x) is f'(x) = df/dx
Thus you want to know where
f'(x) = 3x^2 -6 = -1
3x^2 = 5
x = +or- sqrt(5/3)
= +1.291 or -1.291
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