Plug x=1 and y=8 into the two equations simultaneously and see if both are satisfied.
They both are.
2 + 48 = 50
10 = 10
Therefore (1,8) is the solution.
Your equation y=50-2x
is wrong.
Determine whether the point (1, 8) is a solution of the system
2x + 6y = 50
10x + 0y = 10
by substituting the point into each equation.
So far I have:
2x=6y=50
y=50-2x
10x+10y=10
10x+0(50-2x)=10
10x+0=10
x=10
y=50-2x
y=50-2(1)
y=50-2
y=48
PLEASE HELP! I'm lost. I've had tutoring and still do not understand fully.
2 answers
You are confusing SOLVING the two equations (which is possible by various means) with TRYING OUT a sample solution you have been given, to see if it works.
You have made the problem harder than it really is, and made mistakes in the process.
You have made the problem harder than it really is, and made mistakes in the process.
1 answer