Question

Solve the system of two linear equations.
−3x−4y=−23
−
3
𝑥
−
4
𝑦
=
−
23

3x−5y=5
3
𝑥
−
5
𝑦
=
5
(1 point)
Responses

(−5, 2)
(
−
5
,

2
)
left parenthesis negative 5 comma 2 right parenthesis

(5,−2)
(
5
,
−
2
)
left parenthesis 5 comma negative 2 right parenthesis

(5, 2)
(
5
,

2
)
left parenthesis 5 comma 2 right parenthesis

(−5,−2)

Answer 1

Solve by adding the equations:
-3x−4y = −23
3x−5y = 5
Add: (-4y−5y) = −23+5 → −9y = −18 → y = 2.
Substitute into 3x−5(2)=5 → 3x−10=5 → 3x=15 → x=5.

Solution: (5, 2).