A ladder 10 ft long rests against a vertical wall. let θ be the angle between the top of the ladder and the wall and let x be the distance from the bottom of the ladder to the wall. If the bottom of the ladder slides away from the wall, how fast does x change with respect to θ when θ = π/3

Answer 1

We know that x=Lsin(θ), where L=length of ladder = 10'.

x(θ)=L sin(θ)
x'(θ)=dx/dθ = L cos(θ)

Calculate x'(π/3).