Question
Select the choice that indicates
is the perpendicular bisector of
if they intersect at
.
(1 point)
AB
←→
CD
←→
P
AB ⊥ and
¯¯¯¯¯¯¯¯
CD
¯¯¯¯¯¯¯¯
CP ≅
¯¯¯¯¯¯¯¯
DP ¯¯¯¯¯¯¯¯
CD ⊥
¯¯¯¯¯¯¯¯
AB
¯¯¯¯¯¯¯¯
AP ≅
¯¯¯¯¯¯¯¯
BP ¯¯¯¯¯¯¯¯
AC ⊥ and
¯¯¯¯¯¯¯¯
BD ¯¯¯¯¯¯¯¯
AP ≅
¯¯¯¯¯¯¯¯
BP ¯¯¯¯¯¯¯¯
is the perpendicular bisector of
if they intersect at
.
(1 point)
AB
←→
CD
←→
P
AB ⊥ and
¯¯¯¯¯¯¯¯
CD
¯¯¯¯¯¯¯¯
CP ≅
¯¯¯¯¯¯¯¯
DP ¯¯¯¯¯¯¯¯
CD ⊥
¯¯¯¯¯¯¯¯
AB
¯¯¯¯¯¯¯¯
AP ≅
¯¯¯¯¯¯¯¯
BP ¯¯¯¯¯¯¯¯
AC ⊥ and
¯¯¯¯¯¯¯¯
BD ¯¯¯¯¯¯¯¯
AP ≅
¯¯¯¯¯¯¯¯
BP ¯¯¯¯¯¯¯¯
Answers
GPT-5 mini
AB ⟂ CD and CP ≅ DP
(For AB to be the perpendicular bisector of CD it must be perpendicular to CD and pass through its midpoint, so CP = DP.)
(For AB to be the perpendicular bisector of CD it must be perpendicular to CD and pass through its midpoint, so CP = DP.)