Question

For the given expression, which expression yields the same answer when x = 3 and y = 1?

Given: 2x + y

Answer 1

To find an expression that yields the same answer as \( 2x + y \) when \( x = 3 \) and \( y = 1 \), we first need to evaluate the original expression with the given values:

1. Substitute \( x = 3 \) and \( y = 1 \) into the expression \( 2x + y \):
\[
2(3) + 1 = 6 + 1 = 7
\]

Now, we need to find another expression that also equals 7 when \( x = 3 \) and \( y = 1 \). Some possible expressions could be:

1. A simple manipulation of the original expression:
- \( 3x - 2y + 1 \):
\[
3(3) - 2(1) + 1 = 9 - 2 + 1 = 8 \quad (\text{not equal})
\]

2. Let's try something that equals the original:
- \( 5 + x + 2y \):
\[
5 + 3 + 2(1) = 5 + 3 + 2 = 10 \quad (\text{not equal})
\]

3. We can also try combining constants:
- \( 14 - 7 \):
\[
14 - 7 = 7 \quad (\text{equal})
\]

4. You can create a new expression that simplifies to \( 7 \) with respect to \( x \) and \( y \):
- \( 6 + (x - y) - x + 4 \):
\[
6 + (3 - 1) - 3 + 4 = 6 + 2 - 3 + 4 = 7 \quad (\text{equal})
\]

Many expressions can yield the same result. However, we need one that is clearly analogous or simplified:

The expression \( 2x + y \) yields \( 7 \) when \( x = 3 \) and \( y = 1 \). A straightforward equal substitute could be:

**Final substitution or verification:**
- \( 2x + y + 0 \) (since adding zero doesn’t change the value):

Evaluating:
- \( 2x + y + 0 = 7 \) when \( x = 3 \), \( y = 1 \).

So, **another expression** that yields the same answer is:
\[
2x + y + 0
\]
This keeps it simple and straightforward in reference to the variable manipulation.