Question
The area of the triangle below is 2/15 ft
square feet. What is the length of the base? Express your answer as a fraction in simplest form.
2/5 ft
square feet. What is the length of the base? Express your answer as a fraction in simplest form.
2/5 ft
Answers
GPT-4o mini
To find the length of the base of the triangle, we can use the formula for the area of a triangle:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
In this case, we know the area is \( \frac{2}{15} \) square feet and the height (which we'll denote as \( h \)) is \( \frac{2}{5} \) feet. We can rearrange the formula to solve for the base:
\[
\frac{2}{15} = \frac{1}{2} \times \text{base} \times \frac{2}{5}
\]
Now we multiply both sides of the equation by 2 to eliminate the fraction:
\[
\frac{4}{15} = \text{base} \times \frac{2}{5}
\]
Next, we can solve for the base by multiplying both sides by the reciprocal of \( \frac{2}{5} \):
\[
\text{base} = \frac{4}{15} \times \frac{5}{2}
\]
Now we perform the multiplication:
\[
\text{base} = \frac{4 \times 5}{15 \times 2} = \frac{20}{30}
\]
Now we simplify \( \frac{20}{30} \):
\[
\frac{20}{30} = \frac{2}{3}
\]
Thus, the length of the base is
\[
\boxed{\frac{2}{3}} \text{ ft}
\]
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
In this case, we know the area is \( \frac{2}{15} \) square feet and the height (which we'll denote as \( h \)) is \( \frac{2}{5} \) feet. We can rearrange the formula to solve for the base:
\[
\frac{2}{15} = \frac{1}{2} \times \text{base} \times \frac{2}{5}
\]
Now we multiply both sides of the equation by 2 to eliminate the fraction:
\[
\frac{4}{15} = \text{base} \times \frac{2}{5}
\]
Next, we can solve for the base by multiplying both sides by the reciprocal of \( \frac{2}{5} \):
\[
\text{base} = \frac{4}{15} \times \frac{5}{2}
\]
Now we perform the multiplication:
\[
\text{base} = \frac{4 \times 5}{15 \times 2} = \frac{20}{30}
\]
Now we simplify \( \frac{20}{30} \):
\[
\frac{20}{30} = \frac{2}{3}
\]
Thus, the length of the base is
\[
\boxed{\frac{2}{3}} \text{ ft}
\]