Question

Two workers are pushing on the same large crate. One worker pushes east with a force of 875 N, while the other worker pushes north with a force of 960 N. Friction between the crate and the floor is directed west with a force of 80 N and south with a force of 105 N. Assuming drag due to air resistance is negligible, what are the total north-south net forces and the total east-west net forces acting on the crate, causing it to accelerate across the floor?(1 point)
Responses

855 N to the north and 795 N to the east
855 N to the north and 795 N to the east

855 N to the south and 759 N to the west
855 N to the south and 759 N to the west

795 N to the south and 855 N to the west
795 N to the south and 855 N to the west

795 N to the north and 855 N to the east

Answer 1

To determine the total net forces acting on the crate, we need to calculate the net forces in both the north-south and east-west directions.

### North-South Direction
1. **Worker pushing north:** 960 N
2. **Friction acting south:** 105 N

The net force in the north-south direction can be calculated as follows:
\[
\text{Net North-South Force} = \text{Force North} - \text{Force South} = 960 \, \text{N} - 105 \, \text{N} = 855 \, \text{N} \, \text{to the north}
\]

### East-West Direction
1. **Worker pushing east:** 875 N
2. **Friction acting west:** 80 N

The net force in the east-west direction can be calculated as follows:
\[
\text{Net East-West Force} = \text{Force East} - \text{Force West} = 875 \, \text{N} - 80 \, \text{N} = 795 \, \text{N} \, \text{to the east}
\]

### Summary of Forces
- Total net north-south force: **855 N to the north**
- Total net east-west force: **795 N to the east**

Thus, the correct response is:
**855 N to the north and 795 N to the east.**