Question

Solve the inequality below.

2(6x + 3) ≥ 9x + 12

Group of answer choices

x ≤ 6

x ≤ 2

x ≥ 2

x ≥ 6

Answer 1

To solve the inequality \( 2(6x + 3) \geq 9x + 12 \), we will follow these steps:

1. Distribute the 2 on the left side:
\[
12x + 6 \geq 9x + 12
\]

2. Subtract \( 9x \) from both sides:
\[
12x - 9x + 6 \geq 12
\]
\[
3x + 6 \geq 12
\]

3. Subtract 6 from both sides:
\[
3x \geq 12 - 6
\]
\[
3x \geq 6
\]

4. Divide both sides by 3:
\[
x \geq 2
\]

Thus, the solution to the inequality is:
\[
x \geq 2
\]

The correct answer choice is:
- **x ≥ 2**