Question
(-5 minus square root of 3) (-2 minus square root of 33)
Answers
GPT-4o mini
To simplify the expression \((-5 - \sqrt{3})(-2 - \sqrt{33})\), we can use the distributive property (also known as the FOIL method for binomials):
1. **First**: Multiply the first terms:
\[
(-5) \times (-2) = 10
\]
2. **Outer**: Multiply the outer terms:
\[
(-5) \times (-\sqrt{33}) = 5\sqrt{33}
\]
3. **Inner**: Multiply the inner terms:
\[
(-\sqrt{3}) \times (-2) = 2\sqrt{3}
\]
4. **Last**: Multiply the last terms:
\[
(-\sqrt{3}) \times (-\sqrt{33}) = \sqrt{3} \times \sqrt{33} = \sqrt{99} = 3\sqrt{11}
\]
Now, combine all these results:
\[
10 + 5\sqrt{33} + 2\sqrt{3} + 3\sqrt{11}
\]
So the final result is:
\[
10 + 5\sqrt{33} + 2\sqrt{3} + 3\sqrt{11}
\]
1. **First**: Multiply the first terms:
\[
(-5) \times (-2) = 10
\]
2. **Outer**: Multiply the outer terms:
\[
(-5) \times (-\sqrt{33}) = 5\sqrt{33}
\]
3. **Inner**: Multiply the inner terms:
\[
(-\sqrt{3}) \times (-2) = 2\sqrt{3}
\]
4. **Last**: Multiply the last terms:
\[
(-\sqrt{3}) \times (-\sqrt{33}) = \sqrt{3} \times \sqrt{33} = \sqrt{99} = 3\sqrt{11}
\]
Now, combine all these results:
\[
10 + 5\sqrt{33} + 2\sqrt{3} + 3\sqrt{11}
\]
So the final result is:
\[
10 + 5\sqrt{33} + 2\sqrt{3} + 3\sqrt{11}
\]