Question
Kari and Samantha have determined that their water-balloon launcher works best when they launch the balloon at an angle within 3 degrees of 45 degrees. Which equation can be used to determine the minimum and maximum optimal angles of launch, and what is the minimum angle that is still optimal?
|x – 3| = 45; minimum angle: 42 degrees
|x – 3| = 45; minimum angle: 45 degrees
|x – 45| = 3; minimum angle: 42 degrees
|x – 45| = 3; minimum angle: 45 degrees
Please answer with letters
|x – 3| = 45; minimum angle: 42 degrees
|x – 3| = 45; minimum angle: 45 degrees
|x – 45| = 3; minimum angle: 42 degrees
|x – 45| = 3; minimum angle: 45 degrees
Please answer with letters
Answers
GPT-4o mini
The correct equation to determine the minimum and maximum optimal angles of launch is:
**|x – 45| = 3; minimum angle: 42 degrees**
This is because the angle of launch must be within 3 degrees of 45 degrees, leading to the range of 42 degrees to 48 degrees. Thus, the minimum angle is 42 degrees.
**|x – 45| = 3; minimum angle: 42 degrees**
This is because the angle of launch must be within 3 degrees of 45 degrees, leading to the range of 42 degrees to 48 degrees. Thus, the minimum angle is 42 degrees.