Question

Use the following setup and given equation to find your solution:

1st integer = x

2nd integer = x+2

3rd integer = x+4

Equation: x+(x+2)+(x+4)=120





Solve the equation above. What is the largest of the three integers?

(1 point)
Responses

38, 42, 44
38, 42, 44

38
38

42
42

44
44

Answer 1

To solve the equation \( x + (x + 2) + (x + 4) = 120 \):

1. Combine like terms on the left side:
\[
x + x + 2 + x + 4 = 120 \implies 3x + 6 = 120
\]

2. Subtract 6 from both sides:
\[
3x = 120 - 6 \implies 3x = 114
\]

3. Divide both sides by 3:
\[
x = \frac{114}{3} \implies x = 38
\]

Now we can find the three integers:
- 1st integer = \( x = 38 \)
- 2nd integer = \( x + 2 = 40 \)
- 3rd integer = \( x + 4 = 42 \)

The largest of the three integers is:
**42**

The correct response is:
**42**