Question

Question at position 3
3

Fill in the Blank
10 points



Question at position 3
It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90 m/s2, determine the speed of the Jaguar before it began to skid.

x = Question Blank 1 of 6
Answer

Vi = Question Blank 2 of 6
Answer

Vf = Question Blank 3 of 6
Answer

a = Question Blank 4 of 6
Answer

t = Question Blank 5 of 6
Answer

Which equation should be used? Question Blank 6 of 6
Answer

Answer 1

To solve the problem of determining the speed of the Jaguar before it began to skid, we can use the following kinematic equation:

\[
V_f^2 = V_i^2 + 2a x
\]

Where:
- \(V_f\) is the final velocity (0 m/s, since the Jaguar comes to a stop),
- \(V_i\) is the initial velocity (the speed we are trying to find),
- \(a\) is the acceleration (-3.90 m/s², since the Jaguar is decelerating),
- \(x\) is the distance (290 m, the length of the skid marks).

Now, let's fill in the blanks:

**Question Blank 1:**
- \(x = 290 \, \text{m}\)

**Question Blank 2:**
- \(V_i = ?\) (This is what we need to calculate.)

**Question Blank 3:**
- \(V_f = 0 \, \text{m/s}\)

**Question Blank 4:**
- \(a = -3.90 \, \text{m/s}^2\)

**Question Blank 5:**
- \(t = ?\) (We don't need to calculate time for this equation.)

**Question Blank 6:**
- The equation to use: \(V_f^2 = V_i^2 + 2a x\)

Now we can rearrange the equation to solve for \(V_i\):

\[
0 = V_i^2 + 2(-3.90)(290)
\]
\[
V_i^2 = -2(-3.90)(290)
\]
\[
V_i^2 = 2(3.90)(290)
\]
\[
V_i^2 = 2262
\]
\[
V_i = \sqrt{2262} \approx 47.6 \, \text{m/s}
\]

Thus, the final values you should have are:

- **Question Blank 1 (x)**: \(290 \, \text{m}\)
- **Question Blank 2 (Vi)**: \(47.6 \, \text{m/s}\)
- **Question Blank 3 (Vf)**: \(0 \, \text{m/s}\)
- **Question Blank 4 (a)**: \(-3.90 \, \text{m/s}^2\)
- **Question Blank 5 (t)**: We don't need this value, it can be left blank or marked as not applicable.
- **Question Blank 6**: \(V_f^2 = V_i^2 + 2a x\)