Question

A penny weighs 5.8×10−3
lb. How many pennies are in a pile of pennies that weighs 3.596×104
lb.? Write the answer in scientific notation.(1 point)
Responses

6.2×106
6.2 times 10 superscript 6 baseline

0.62×107
0.62 times 10 superscript 7 baseline

6.2×10−7
6.2 times 10 superscript negative 7 baseline

6.2×108

Answers

GPT-4o mini
To find out how many pennies are in a pile that weighs \( 3.596 \times 10^4 \) lb, we can use the weight of one penny, which is \( 5.8 \times 10^{-3} \) lb.

To calculate the number of pennies, we divide the total weight by the weight of one penny:

\[
\text{Number of pennies} = \frac{\text{Total weight}}{\text{Weight of one penny}} = \frac{3.596 \times 10^4 \text{ lb}}{5.8 \times 10^{-3} \text{ lb}}
\]

Performing the division:

\[
\text{Number of pennies} = \left( \frac{3.596}{5.8} \right) \times \left( \frac{10^4}{10^{-3}} \right)
\]

Calculating \( \frac{3.596}{5.8} \):

\[
\frac{3.596}{5.8} \approx 0.6196551724 \approx 0.62
\]

Next, for the powers of ten:

\[
\frac{10^4}{10^{-3}} = 10^{4 - (-3)} = 10^{4 + 3} = 10^7
\]

Now combine the two results:

\[
\text{Number of pennies} \approx 0.62 \times 10^7
\]

To express this in scientific notation, we can rewrite \( 0.62 \) as \( 6.2 \times 10^{-1} \):

\[
0.62 \times 10^7 = 6.2 \times 10^{-1} \times 10^7 = 6.2 \times 10^{7 - 1} = 6.2 \times 10^6
\]

Thus, the number of pennies in the pile is:

\[
\boxed{6.2 \times 10^6}
\]