Question

A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105
gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)
Responses

54.78×105
lb.
54.78 times 10 superscript 5 baseline lb.

5.478×105
lb.
5.478 times 10 superscript 5 baseline lb.

5.478×106
lb.
5.478 times 10 superscript 6 baseline lb.

54.78×106
lb.

Answer 1

To calculate the weight of the water in an Olympic-sized swimming pool, we can use the following information:

- Weight of water per gallon: 8.3 lb
- Volume of the swimming pool: \(6.6 \times 10^5\) gallons

The weight of the water can be calculated using:

\[
\text{Total weight} = \text{Weight per gallon} \times \text{Number of gallons}
\]

Substituting the given values:

\[
\text{Total weight} = 8.3 \, \text{lb/gallon} \times 6.6 \times 10^5 \, \text{gallons}
\]

Calculating this step-by-step:

1. Calculate \(8.3 \times 6.6\):
\[
8.3 \times 6.6 = 54.78
\]

2. Now include the factor of \(10^5\):
\[
\text{Total weight} = 54.78 \times 10^5 \, \text{lb}
\]

This can also be expressed in scientific notation by converting it to the form \(a \times 10^n\):

\[
54.78 \times 10^5 \, \text{lb} = 5.478 \times 10^6 \, \text{lb}
\]

Thus, the approximate weight of the water in an Olympic-sized swimming pool is:

\[
\boxed{5.478 \times 10^6 \, \text{lb}}
\]