Asked by Jon
What is the domain and range of the following function?
f(x)= - sqrt(-lnx+2)
For the domain, I got 0<x<or equal to e^2
Is this right?
And can someone help with range?
f(x)= - sqrt(-lnx+2)
For the domain, I got 0<x<or equal to e^2
Is this right?
And can someone help with range?
Answers
Answered by
Reiny
correct
And what did you get for your range?
And what did you get for your range?
Answered by
Jon
I'm not sure what to do for the range?
Can you help please?
Can you help please?
Answered by
Jon
is it just YER?
Answered by
Reiny
When you take the derivative and set it equal to zero, there is no solution.
So the function has no local max/mins
So consider the endpoints of your domain
let x --- 0 from the right
lnx will be hugely negativae, so -lnx will be hugely positive , adding 2 to it won't matter much.
so √big will be big
and -√big will be -big, so the graph approaches negative infinity along the y-axis.
other endpoint, x = e^2
y = -√(-2+2) = -√0 = 0
range: -negative infinity to 0
So the function has no local max/mins
So consider the endpoints of your domain
let x --- 0 from the right
lnx will be hugely negativae, so -lnx will be hugely positive , adding 2 to it won't matter much.
so √big will be big
and -√big will be -big, so the graph approaches negative infinity along the y-axis.
other endpoint, x = e^2
y = -√(-2+2) = -√0 = 0
range: -negative infinity to 0
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