Question

A gallon of water weighs about 8.3 lb. An Olympic-sized swimming pool holds 6.6×105
gallons. What is the approximate weight of the water in an Olympic-sized swimming pool? Write the answer in scientific notation.(1 point)
Responses

5.478×105
lb.
5.478 times 10 superscript 5 baseline lb.

54.78×106
lb.
54.78 times 10 superscript 6 baseline lb.

5.478×106
lb.
5.478 times 10 superscript 6 baseline lb.

54.78×105
lb.

Answer 1

To find the weight of the water in an Olympic-sized swimming pool, we can multiply the weight of one gallon of water by the number of gallons in the pool.

1. **Weight of one gallon of water**: 8.3 lb
2. **Number of gallons in an Olympic-sized swimming pool**: \(6.6 \times 10^5\) gallons

Now calculate the total weight of the water:

\[
\text{Total weight} = \text{Weight of one gallon} \times \text{Number of gallons} = 8.3 \, \text{lb} \times 6.6 \times 10^5 \, \text{gallons}
\]

Calculating the multiplication:

\[
8.3 \times 6.6 = 54.78
\]

Thus, the total weight becomes:

\[
\text{Total weight} = 54.78 \times 10^5 \, \text{lb}
\]

Now, to express it in proper scientific notation, we can rewrite \(54.78 \times 10^5\) as:

\[
5.478 \times 10^6 \, \text{lb}
\]

Therefore, the weight of the water in an Olympic-sized swimming pool is approximately:

\[
\boxed{5.478 \times 10^6} \, \text{lb}
\]